a) x ² + x – 6/x ² + 4x + 3 . x ² – 4x – 5/x ² – 10x + 25
b) x(y ² – z) + y(x – xy)/(x – y) ² + (y – z) ² + (z – x) ² : xy ² – xz . (2y – z)/2(x ³+ y ³ + z ³ – 3xyz)
c) 2x ³ – 2y ³/3x + 3y . x ² + 2xy + y ²/2x ² + 2xy + y ²
d) x ³y -xy ³/5x ² + 5y ² . x ² + y ²/x ²y + xy ²
e) 2x ² – 50/x ² + 3x : x ² + 5x/x ² + 6x + 9
g) x ² + xy/2x ² – 2xy ² : x ² + xy + y ²/2x ³ – 2y ³
a) x ² + x – 6/x ² + 4x + 3 . x ² – 4x – 5/x ² – 10x + 25 b) x(y ² – z) + y(x – xy)/(x – y) ² + (y – z) ² + (z – x) ² : xy ² – xz . (2y – z)/2(x ³+ y
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Đáp án: a) $4\,{x}^{2}-11\,{x}^{-2}-10\,x+25$
b) $x \left( {y}^{2}-z \right) +{\frac {yx}{ \left( x-y \right) ^{2}}}-{
\frac {y{\it xy}}{ \left( x-y \right) ^{2}}}+{\frac {{x}^{2}}{{{\it xy
}}^{2}}}-2\,{\frac {zx}{{{\it xy}}^{2}}}+{\frac {{z}^{2}}{{{\it xy}}^{
2}}}-{\it xz} \left( 2\,y-{\frac {z}{2\,{x}^{3}+2\,{y}^{3}+2\,{z}^{3}-
6\,{\it xyz}}} \right) ^{-1}$
c) $1/6\,{\frac {12\,{x}^{5}+6\,{y}^{2}{x}^{2}+18\,{{\it yx}}^{2}{x}^{2}-4
\,{y}^{3}x+24\,{\it xy}\,{x}^{2}+3\,{y}^{2}}{{x}^{2}}}$
d) $1/5\,{\frac {5\,{x}^{5}y+25\,{y}^{2}{x}^{4}+5\,{{\it xy}}^{2}{x}^{2}-{
{\it xy}}^{3}+5\,y}{{x}^{2}}}$
e) ${\frac {2\,{x}^{4}+6\,{x}^{3}+9\,{x}^{2}+8\,x-50}{{x}^{2}}}$
g) $1/2\,{\frac {-4\,{y}^{3}{x}^{3}+2\,{x}^{5}+4\,{\it xy}\,{x}^{3}-4\,{{
\it xy}}^{2}x+{\it xy}\,x+{y}^{2}}{{x}^{3}}}$
Giải thích các bước giải: CHo nguyên cái đề luôn lười làm giải thích lắm
$#Ben347$
Đáp án: a) $4\,{x}^{2}-11\,{x}^{-2}-10\,x+25$
b)$x \left( {y}^{2}-z \right) +{\frac {yx}{ \left( x-y \right) ^{2}}}-{ \frac {y{\it xy}}{ \left( x-y \right) ^{2}}}+{\frac {{x}^{2}}{{{\it xy }}^{2}}}-2\,{\frac {zx}{{{\it xy}}^{2}}}+{\frac {{z}^{2}}{{{\it xy}}^{ 2}}}-{\it xz} \left( 2\,y-{\frac {z}{2\,{x}^{3}+2\,{y}^{3}+2\,{z}^{3}- 6\,{\it xyz}}} \right) ^{-1}$
c) $\frac{1}{6}\,{\frac {12\,{x}^{5}+6\,{y}^{2}{x}^{2}+18\,{{\it yx}}^{2}{x}^{2}-4 \,{y}^{3}x+24\,{\it xy}\,{x}^{2}+3\,{y}^{2}}{{x}^{2}}}$
d) $\frac{1}{5}\,{\frac {5\,{x}^{5}y+25\,{y}^{2}{x}^{4}+5\,{{\it xy}}^{2}{x}^{2}-{ {\it xy}}^{3}+5\,y}{{x}^{2}}}$
e) ${\frac {2\,{x}^{4}+6\,{x}^{3}+9\,{x}^{2}+8\,x-50}{{x}^{2}}}$
g) $\frac{1}{2} \,{\frac {-4\,{y}^{3}{x}^{3}+2\,{x}^{5}+4\,{\it xy}\,{x}^{3}-4\,{{ \it xy}}^{2}x+{\it xy}\,x+{y}^{2}}{{x}^{3}}}$